If 40 ml of 0.2 m koh
WebA sample of 100 ml of 0.10 M acid HA K a =1 × 10 5 is titrated with standard 0.10 M KOH.How many ml of KOH will have to be added when the pH in the titration flask will be 5.00 ?A. 0B. 10C. 100D. 50. Login. Study Materials. NCERT Solutions. NCERT Solutions For … WebIf 50 mL of 0.2 M KOH is added to 40 mL of 0.5 M HCOOH, the pH of the resulting solution is (Ka = 1.8 × 10–4) : amogh joshi, 8 years ago Grade:12 2 Answers Sunil Kumar FP askIITians Faculty 183 Points 8 years ago KOH + HCOOH ---------HCOOK +H2O .01 ,02 0 0 .01 .01 pH =pKA +log (salt)/ (acid) =-logK +log (.01/.01) =3.744 Rishi Sharma
If 40 ml of 0.2 m koh
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Web1 jul. 2024 · asked Jul 1, 2024 in Chemistry by Khushisingh (24.6k points) If 50ml 50 m l of 0.2M K OH 0.2 M K O H is added to 40ml 40 m l of 0.5M H C OOH 0.5 M H C O O H, … Web19 jan. 2024 · If `50ml` of `0.2 M KOH` is added to `40 ml` of `0.05 M HCOOH`, the `pH` of the resulting solution is (`K_(a)=1.8xx10^(-4)`) AboutPressCopyrightContact...
WebIf 50 mL of 0.2 M KOH is added to 40 mL of 0.5 M HCOOH, the pH of the resulting solution is (Ka = 1.8 × 10–4) : amogh joshi, 8 years ago Grade:12 2 Answers Sunil Kumar FP … WebFor 200 ml of 0.1 M solution, you’ll need 0.2 L * 0.1 M = 0.02 moles of KOH. Molar weight of KOH is 56.1 g/mol. That means that 0.02 moles of KOH is 0.02 mol * 56.1 g/mol = 1.122g of KOH. You can easily round that up to 1.12g - it’ll be easier to weight it as well. 4.3K views Sirach Ruksana
WebFor 200 ml of 0.1 M solution, you’ll need 0.2 L * 0.1 M = 0.02 moles of KOH. Molar weight of KOH is 56.1 g/mol. That means that 0.02 moles of KOH is 0.02 mol * 56.1 g/mol = … WebIf \( 40 \mathrm{ml} \) of \( 0.2 \mathrm{M} \mathrm{KOH} \) is added to \( 160 \mathrm{ml} \) of \( 0.1 \mathrm{M} \)\( \mathrm{HCOOH}\left[\mathrm{K}_{\mat...
Web7 okt. 2024 · Best answer Meq. of H2S04 = 200 x 0.1 x 2 = 40 (H2S04 is dibasic) Meq. of KOH =200 x 0.2 = 40 40 Meq. of H2SO4 and 40 Meq. of KOH on mixing gives heat = 2.3 kJ 1000 Meq. of H2SO4 and 1000 Meq. of KOH on mixing gives heat = 2.3 x100 /40 = 57.5 kJ ← Prev Question Next Question → Find MCQs & Mock Test Free JEE Main Mock Test …
Web14 jun. 2024 · If 50ml 50 m l of 0.2M K OH 0.2 M K O H is added to 40ml 40 m l of 0.5M H C OOH 0.5 M H C O O H, the pH p H of the resulting solution is (K a = 1.8 × 10−4 K a = 1.8 … girl lured onlineWeb4. a) Calculate the pH of a solution that is 0.60 M HNO2 and 0.40 M NaNO2. This is a buffer: we have a weak acid, HNO2, and its conjugate base, NO2 [acid] [base] pH = pKa + log (0.60 M) (0.40 M) pH = -log(4.5 x 10-4 ) + log pH = 3.35 + log(0.67) = 3.35 + (-0.18) = 3.17 b) Calculate the pH after 0.01 mol NaOH is added to 500.0 mL of the solution in part A. function sheet bedeutungWebAnswer (1 of 2): For this apply the equivalent concept N1V1=N2V2 As normality cab be written as molarity × n factor M1V1×n1=M2V2×n2 Here as the given compound are acid and base we can determine n factor as number of H+ ions or OH- to be released respectively. So n factor for H3PO4 is 3 n fa... functions for beginnersWebWhen 10 mL of 0.1 M acetic acid (p K a = 5.0) is titrated against 10 mL of 0.1 M ammonia solution (p K b = 5.0) the equivalence point occurs at pH of: Q. A weak base B O H was titrated against a strong acid. The p H at 1 4 th equivalence point was 9.24. functions for inhaling and exhaling processgirl lunch boxes on amazonWebAnswer (1 of 2): 3KOH (aq) + H3PO4 —————-> K3PO4 (aq) + 3H2O mole ratio. 3:1 25.0 cm3 of 0.2 M KOH reacted with 50 cm3 of unknown concentration of H3PO4 [25.0/1000] x 0.2 M = 0.05 moles KOH moles of H3PO4 = {50.0 /1000} x concentration = 0.0167 moles H3PO4 Molarity of H3PO4 = (1000 X 0.0167)... functions f and gWebIf 40 ml of 0.2 M KOH is added to 160 ml of 0.1 M HCOOH [Ka = 2 × 10^-4] , the pOH of the resulting solution is: Class 11. >> Chemistry. >> Equilibrium. >> Ionization of Acids and … girlly cast.com